(CodeUp) 코드업 1922 - Python - [재귀함수] 3n+1

def recursion(n):
    if n==1:
        return 1
    elif n%2==1:
        return recursion(3*n+1) + 1
    elif n%2==0:
        return recursion(n/2) + 1 
        
n = int(input())
result = recursion(n)
print(result)